For the feedback system shown, the transfer function \(\dfrac{E(s)}{R(s)}\) is:
Step 1: Write the standard feedback equation.
For unity summing junction:
\[
E(s) = R(s) - H(s)C(s)
\]
Step 2: Substitute forward path output.
Since \(C(s) = G(s)E(s)\):
\[
E(s) = R(s) - H G E(s)
\]
Step 3: Solve for \(\dfrac{E(s)}{R(s)}\).
\[
E(s)(1 + GH) = R(s)
\]
\[
\frac{E(s)}{R(s)} = \frac{1}{1 + GH}
\]
Step 4: Conclusion.
The correct option is (C).
Final Answer: \(\boxed{\dfrac{1}{1+GH}}\)

Using masons gain formula, find the non-touching loops in terms of loop gains:
In the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage \( E \) for unit change in the resistance \( R \), in V/Ω, is __________ (round off to two decimal places).
