Question:
For the cell reaction
\(2Fe^{3+}+2I^{-}_{(aq)}\rightarrow2Fe^{2+}+I_2{(aq)}\)
\(E^{\ominus}_{cell}=0.24\ V \ at \ 298 k.\)The standard Gibbs energy \((\Delta_rG^{\ominus})\) of the cell reaction is:
[Given that Faraday constant \( F=96500 \ C\ mol^{-1}]\)
For the cell reaction
\(2Fe^{3+}+2I^{-}_{(aq)}\rightarrow2Fe^{2+}+I_2{(aq)}\)
\(E^{\ominus}_{cell}=0.24\ V \ at \ 298 k.\)The standard Gibbs energy \((\Delta_rG^{\ominus})\) of the cell reaction is:
[Given that Faraday constant \( F=96500 \ C\ mol^{-1}]\)
\(2Fe^{3+}+2I^{-}_{(aq)}\rightarrow2Fe^{2+}+I_2{(aq)}\)
\(E^{\ominus}_{cell}=0.24\ V \ at \ 298 k.\)The standard Gibbs energy \((\Delta_rG^{\ominus})\) of the cell reaction is:
[Given that Faraday constant \( F=96500 \ C\ mol^{-1}]\)
Updated On: May 21, 2024
- \(-46.32 \ kjmol{-1}\)
- \(-23.16 \ kjmol{-1}\)
- \(46.32 \ kjmol{-1}\)
- \(23.16\ kjmol{-1}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A) :\(-46.32 \ kjmol{-1}\)
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