The coagulation of a negatively charged sol, such as \( \text{As}_2\text{S}_3 \), is most effective with a highly positively charged ion, according to the Hardy-Schulze rule.
Among the given options:
\( \text{FeCl}_3 \) dissociates to produce \( \text{Fe}^{3+} \), which has the highest positive charge (\( +3 \)).
Higher positive charges effectively neutralize the negative charge of the sol, leading to coagulation.
In contrast, \( \text{CaCO}_3 \) (which produces \( \text{Ca}^{2+} \)) and \( \text{NaCl} \) (which produces \( \text{Na}^+ \)) are less effective because their ions have lower positive charges.
Final Answer:
\[
\boxed{\text{FeCl}_3}
\]