Match List-I with List-II.\[\begin{array}{|c|c|} \hline \text{List-I (Animal)} & \text{List-II (Breed)} \\ \hline \text{(A) Buffalo} & \text{(I) Sunandini} \\ \hline \text{(B) Cow} & \text{(II) White Leghorn} \\ \hline \text{(C) Poultry} & \text{(III) Toggenburg} \\ \hline \text{(D) Goat} & \text{(IV) Nili-Ravi} \\ \hline \end{array}\]Choose the correct answer from the options given below:
| List I (Name of Disease) | List II (Alternate Popular Name of Disease) |
|---|---|
| (A) Inclusion Body Hepatitis | (I) Bird flu |
| (B) New Castle disease | (II) Gumboro disease |
| (C) Infectious Bursal Disease | (III) Leechi Disease |
| (D) Avian Influenza | (IV) Ranikhet disease |
If 0.01 mol of $\mathrm{P_4O_{10}}$ is removed from 0.1 mol, then the remaining molecules of $\mathrm{P_4O_{10}}$ will be:
An element has two isotopes having atomic masses 10 and 15 u, respectively. If the percent abundance of lighter isotopes is 80%, then the average atomic mass of the element is: