Step 1: Analyze the Reaction
The reaction involves KMnO₄/H⁺, which is a typical oxidizing agent that cleaves alkenes and oxidizes the resulting fragments to carboxylic acids.
Step 2: Predict the Major Product
The oxidation of an alkene will cleave the double bond and convert both fragments into carboxylic acids. The correct product is:
$$ \text{COOH} \longrightarrow -C - C \longrightarrow \text{COOH} $$
Conclusion
The correct product is a pair of carboxylic acids formed by cleaving the alkene.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :