Question

For a series combination of resistors, what is the value of \( n \) for the formula \( \frac{n}{n+1} + \frac{1}{R} = \frac{1}{R_{eq}} \)?

• A. \( \frac{5}{2} \)
• B. \( \frac{1}{2} \)
• C. \( \frac{2}{5} \)
• D. \( \frac{3}{2} \)

Hint:

In series circuits, the equivalent resistance is calculated by adding the individual resistances. Use formulas like \( \frac{n}{n+1} \) to simplify such calculations.

Answer 1

The Correct Option is B

Step 1: Understanding the formula.
The formula given represents the relationship between the resistances in a series combination of resistors. It involves the equivalent resistance \( R_{eq} \) of the system and the formula for finding it.
Step 2: Solving for \( n \).
By applying the formula and solving for \( n \), the correct value of \( n \) comes out to be \( \frac{1}{2} \).
Step 3: Conclusion.
The correct value for \( n \) is \( \frac{1}{2} \), so the correct answer is (B).