The slenderness ratio \( \lambda \) for a column is given by the formula:
\[
\lambda = \frac{l}{r}
\]
where:
- \( l \) is the effective length of the column,
- \( r \) is the radius of gyration of the column.
For a circular column, the radius of gyration \( r \) is given by:
\[
r = \sqrt{\frac{I}{A}}
\]
where:
- \( I \) is the moment of inertia of the cross-section,
- \( A \) is the cross-sectional area.
For a circular column of diameter \( d \), the moment of inertia \( I \) and area \( A \) are given by:
\[
I = \frac{\pi d^4}{64} \quad \text{and} \quad A = \frac{\pi d^2}{4}
\]
Substituting for \( r \):
\[
r = \sqrt{\frac{\frac{\pi d^4}{64}}{\frac{\pi d^2}{4}}} = \sqrt{\frac{d^2}{16}} = \frac{d}{4}
\]
Now, using the given slenderness ratio \( \lambda = 160 \), we have:
\[
\lambda = \frac{l}{r} = \frac{l}{\frac{d}{4}} = \frac{4l}{d}
\]
Thus, the ratio \( \frac{l}{d} \) is:
\[
\frac{l}{d} = \frac{\lambda}{4} = \frac{160}{4} = 40
\]
Therefore, the \( l/d \) ratio of the column is 40.