Question

Find the wrong term in the following number series: 1, 1, 2, 4, 3, 6, 4, 16

• A. 4
• B. 3
• C. 6
• D. 16

Hint:

Interleaved series often have a relationship between terms at different positions. Squaring or multiplying by the corresponding term in the other series is a common pattern.

Answer 1

The Correct Option is C

Step 1: Analyze the pattern by looking at interleaved series.
Consider the odd-positioned terms: 1, 2, 3, 4 (an arithmetic progression with a common difference of +1).
Consider the even-positioned terms: 1, 4, 6, 16.
Step 2: Try to find a pattern in the even-positioned terms related to the odd-positioned terms.
The \(n^{th}\) even term might be the square of the \(n^{th}\) odd term.
\( a_2 = (a_1)^2 = 1^2 = 1 \)
\( a_4 = (a_3)^2 = 2^2 = 4 \)
\( a_6 = (a_5)^2 = 3^2 = 9 \) (The term is 6, so its wrong)
\( a_8 = (a_7)^2 = 4^2 = 16 \)
The wrong term is 6.