Find the ratio of the following: - Speed of a cycle \(15\) km per hour to the speed of scooter \(30\) km per hour.
- \(5\) m to \(10\) km
- \(50\) paise to Rs \(5\)
- Speed of a cycle \(15\) km per hour to the speed of scooter \(30\) km per hour.
- \(5\) m to \(10\) km
- \(50\) paise to Rs \(5\)
Solution and Explanation
(a) Ratio of the speed of cycle to the speed of scooter = \(\frac{15}{30}\)
= \(1:2\)
(b) Since \(1\) km = \(1000\) \(m\),
Required ratio = \(\frac{5\; km}{10\;km}\)
= \(\frac{5\;m}{10}× 1000\; m\)
= \(1:2000\)
(c) Since Rs \(1 = 100\) \(\text{paise}\),
Required ratio = \(\frac{50 \;paise}{Rs \;5}\)
= \(\frac{50 \;paise}{500 \;paise}\)
= \(1:10\)
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