Question

Find the number of permutations that can be made from the letters of the word OMEGA, if the vowels occupy odd places.

• A. 12 ways
• B. 6 ways
• C. 13 ways
• D. 17 ways

Answer 1

The Correct Option is A

The vowels in the word OMEGA are O, E, and A, and they must occupy the odd places. 
There are 3 odd positions, so the vowels can be arranged in 3! = 6 ways. 
The remaining consonants (M, G) can be arranged in the 2 even places in 2! = 2 ways. 
Thus, the total number of permutations is \(3! × 2! = 12.\)