The given alpha-numeric series is D4T, F9R, H20P, J43N. Let's analyze the pattern in the letters and the numbers separately.
Letters:
The first letters are D, F, H, J. These are the 4th, 6th, 8th, and 10th letters of the alphabet, respectively. The pattern is \( +2 \) in the position of the letter. The next letter should be the 12th letter, which is L.
The last letters are T, R, P, N. These are the 20th, 18th, 16th, and 14th letters of the alphabet, respectively. The pattern is \( -2 \) in the position of the letter. The next letter should be the 12th letter, which is L.
So, the next term should start with L and end with L.
Numbers:
The numbers are 4, 9, 20, 4(C) Let's find the pattern in this sequence:
\( 9 - 4 = 5 \)
\( 20 - 9 = 11 \)
\( 43 - 20 = 23 \)
The differences are 5, 11, 2(C) Let's look at the differences between these differences:
\( 11 - 5 = 6 \)
\( 23 - 11 = 12 \)
The differences between the differences are 6, 1(B) This suggests that the next difference might be \( 12 \times 2 = 24 \).
So, the next difference in the number sequence would be \( 23 + 24 = 47 \).
Therefore, the next number in the sequence would be \( 43 + 47 = 90 \).
Combining the letter and number patterns, the next term in the series should be L90L.
This corresponds to option (C)