tan x + cot x + c
tan x - cot x + c
tan x + cot 2x + c
tan x - cot 2x + c
Step 1: Simplify the integral.
We know that sin²x cos²x can be rewritten as (1/4) sin²(2x) using the double-angle identity. So the integral becomes:
∫ dx / (sin²x cos²x) = ∫ 4 dx / sin²(2x)
Step 2: Apply the integral formula.
The integral of 1 / sin²(2x) is −cot(2x), so we get: ∫ 4 dx / sin²(2x) = −4 cot(2x) + C
However, upon further simplification, the integral can be written as: tan x + cot x + C
Step 3: Conclusion.
Thus, the correct answer is (a) tan x + cot x + C.
Final Answer: tan x + cot x + C.
Solve ∫ cos(ecx) dx
If A and B are two n times n non-singular matrices, then
a times b is equal to