Find all points of discontinuity of f,where f is defined by
\[f(x) = \begin{cases} \frac {x}{|x|}, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\]\(f(x) = \begin{cases} \frac {x}{|x|}, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\)
It is known that, x<0\(\implies\)|x| = -x
Therefore, the given function can be rewritten as
\(f(x) = \begin{cases} \frac {x}{|x|}=\frac {x}{-x}=-1, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\)
\(\implies\)f(x) = -1 for all x∈R
Let c be a point on the real number.Then, \(\lim\limits_{x \to c}\) f(x) = \(\lim\limits_{x \to c}\) (-1) = -1
Also, f(c) = -1 = \(\lim\limits_{x \to c}\) f(x)
Therefore ,the given function is a continuous function.
Hence, the given function has no point of discontinuity.
The function \( f(x) \) is defined as follows: \[ f(x) = \begin{cases} 2+x, & \text{if } x \geq 0 \\ 2-x, & \text{if } x \leq 0 \end{cases} \] Then function \( f(x) \) at \( x=0 \) is:
A function is said to be continuous at a point x = a, if
limx→a
f(x) Exists, and
limx→a
f(x) = f(a)
It implies that if the left hand limit (L.H.L), right hand limit (R.H.L) and the value of the function at x=a exists and these parameters are equal to each other, then the function f is said to be continuous at x=a.
If the function is undefined or does not exist, then we say that the function is discontinuous.
Conditions for continuity of a function: For any function to be continuous, it must meet the following conditions: