Let the original number be \(N\).
First increase by 20%:
New number \(N_1 = N + 0.20N = (A)20N\)
Second increase by 25% (on \(N_1\)):
Increase \( = 0.25 \times (A)20N = 0.30N \)
New number \(N_2 = (A)20N + 0.30N = (A)50N\)
Third increase by 30% (on \(N_2\)):
Increase \( = 0.30 \times (A)50N = 0.45N \)
Final number \(N_3 = (A)50N + 0.45N = (A)95N\)
The total increase from the original number \(N\) to the final number \(N_3\) is \(N_3 - N = (A)95N - N = 0.95N\).
To find the single equivalent percentage increase, we calculate the percentage of this increase with respect to the original number \(N\):
Equivalent percentage increase \( = \frac{\text{Total Increase}}{\text{Original Number}} \times 100 \)
Equivalent percentage increase \( = \frac{0.95N}{N} \times 100 \)
Equivalent percentage increase \( = 0.95 \times 100 = 95 \)
Therefore, the single equivalent increase is 95%.