Figure 9.21 (a) shows a thin liquid film supporting a small weight = 4.5 × 10-2 N. What is the weight supported by a film of the same liquid at the same temperature in Fig. (b) and (c) ? Explain your answer physically.
Take case (a):
The length of the liquid film supported by the weight, l = 40 cm = 0.4 cm
The weight supported by the film, W = 4.5 × 10-2 N
A liquid film has two free surfaces.
∴ Surface tension = \(\frac{W }{ 2l} \)
\(= \frac{4.5 × 10 - 2 }{ 2 × 0.4 }\)
= 5.625 × 10 - 2 N m-1
In all the three figures, the liquid is the same. Temperature is also the same for each case. Hence, the surface tension in figure (b) and figure (c) is the same as in figure (a), i.e., 5.625 × 10–2 N m–1. Since the length of the film in all the cases is 40 cm, the weight supported in each case is 4.5 × 10-2 N.
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.
Surface tension is defined as,
The ratio of the surface force F to the length L along which the force acts.
Mathematically, the surface tension formula can be expressed as follows:
T=F/L
Where,
Read More: Detergents and Surface Tension
The SI unit of Surface Tension is Newton per Meter or N/m.