Question:

Excess of NaOH reacts with Zn to form:

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Excess NaOH reacts with Zn to form zinc hydroxide, which is a white precipitate.
Updated On: Jan 6, 2026
  • \( \text{ZnOH}_2 \)
  • \( \text{NaZnOH}_3 \)
  • \( \text{ZnO}_2 \)
  • \( \text{Zn(OH)}_2 \)
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The Correct Option is D

Solution and Explanation

Step 1: Reaction of Zn with NaOH. When zinc reacts with excess sodium hydroxide (NaOH), zinc hydroxide \( \text{Zn(OH)}_2 \) is formed. This is a white precipitate.
Step 2: Conclusion. Thus, the correct answer is \( \text{Zn(OH)}_2 \).
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