Question:

Excess of ammonia with sodium hypochloride solution in the presence of glue or gelatin gives

Updated On: Jul 13, 2024
  • $\ce{NaNH2 }$
  • $\ce{NH2NH2 }$
  • $\ce{ N_2}$
  • $\ce{NH4Cl }$
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The Correct Option is B

Solution and Explanation

Excess of ammonia $\left( NH _{3}\right)$ when reacts with sodium hypochlorite solution (NaOCl) in presence of glue or gelatin gives hydrazine $\left( NH _{2} \cdot NH _{2}\right)$ This process is known as Raschig process

$2 NH _{3}+ NaOCl \to N _{2} H _{4}+ NaCl + H _{2} O$

Addition of gelatin or glue suppress the side reaction by complexing with the metal ions and yield of hydrazine is increased.
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Concepts Used:

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  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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