Question:

Evaluate each of the following:
  1. (–30) ÷ 10
  2. 50 ÷ (–5)
  3. (–36) ÷ (–9)
  4. (– 49) ÷ (49)
  5. 13 ÷ [(–2) + 1]
  6. 0 ÷ (–12)
  7. (–31) ÷ [(–30) + (–1)]
  8. [(–36) ÷ 12] ÷ 3
  9. [(– 6) + 5)] ÷ [(–2) + 1]

Updated On: Sep 10, 2024
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

(a) (-30) ÷ 10 = (-30) × \(\frac {1}{10}\) = \(\frac {-30×1}{10}\) = -3


(b) 50 ÷ (-5) = 50 × \((-\frac 15) \)\(\frac {50×(-1)}{5}\) = -10


(c) (-36) ÷ (-9) = (-36) × \(\frac 19\) = \(\frac {(-36)×(-1)}{9}\) = \(\frac {36}{9}\) = 4


(d) (-49) ÷ (49) = (-49) × \(\frac {1}{49}\)\(\frac {-49}{49}\) = -1


(e) 13 ÷ [(-2) + 1] = 13 ÷ (-1) = 13 × \((\frac {-1}{1})\) = -13


(f) 0 ÷ (–12) = 0 × \((\frac {-1}{12})\) = \(\frac {0}{12}\) = 0
 


(g) (–31) ÷ [(–30) + (–1)] = (-31) ÷ (-30 - 1) = (-31) ÷ (-31) = (-31) × \((\frac {-1}{31})\) = \(\frac {31}{31}\) = 1
 


(h) [(–36) ÷ 12] ÷ 3 = [(-36) ×\(\frac {1}{12}\)] ×\(\frac {1}{3}\)= (-3) × \(\frac 13\) =\( \frac {-3}{3}\) = -1
 


(i) [(– 6) + 5)] ÷ [(–2) + 1] = (-6 + 5) ÷ (-2 + 1) = (-1) ÷ (-1) = (-1) × \(\frac {(-1)}{1}\) = 1

Was this answer helpful?
1
1

Questions Asked in CBSE Class VII exam

View More Questions