Question:

Ethyl methyl ketone is obtained by heating calcium salts of

Updated On: Jun 18, 2022
  • formic acid $ + $ propionic acid
  • acetic acid $ + $ propionic acid
  • acetic acid only
  • acetic acid $ + $ methanoic acid
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The Correct Option is B

Solution and Explanation

26. Ethyl methyl ketone is an unsymmetric ketone, so two different acids (in the form of calcium salt) are used. The structure of ethyl methyl ketone is

$C _{2} H _{5} COCH _{3}$

The structure shows the presence of 4 carbon atoms, thus the calcium salts must be of acetic acid and propionic acid to form $C _{2} H _{5} COCH _{3}$.

$\left( C _{2} H _{5} COO \right)_{2} Ca +\left( CH _{3} COO \right)_{2} Ca \stackrel{\text { Distill }}{\longrightarrow}$
$C _{2} H _{5} COCH _{3}+ CaCO _{3}$
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Concepts Used:

Aldehydes, Ketones, and Carboxylic Acids

Aldehydes, Ketones, and Carboxylic Acids are carbonyl compounds that contain a carbon-oxygen double bond. These organic compounds are very important in the field of organic chemistry and also have many industrial applications.

Aldehydes:

Aldehydes are organic compounds that have the functional group -CHO.

Preparation of Aldehydes

Acid chlorides are reduced to aldehydes with hydrogen in the presence of palladium catalyst spread on barium sulfate.

Ketones:

Ketones are organic compounds that have the functional group C=O and the structure R-(C=O)-R’.

Preparation of Ketones

Acid chlorides on reaction with dialkyl cadmium produce ketones. Dialkyl cadmium themselves are prepared from Grignard reagents.

Carboxylic Acid:

Carboxylic acids are organic compounds that contain a (C=O)OH group attached to an R group (where R refers to the remaining part of the molecule).

Preparation of Carboxylic Acids

Primary alcohols are readily oxidized to carboxylic acids with common oxidizing agents such as potassium permanganate in neutral acidic or alkaline media or by potassium dichromate and chromium trioxide in acidic media.