Question

Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm\(^{-1}\) cm\(^{2}\). If NaF is replaced by KF, what is the value of equivalent conductance?

• A. 90.1 Ohm\(^{-1}\) cm\(^{2}\)
• B. 111.2 Ohm\(^{-1}\) cm\(^{2}\)
• C. 90.1 Ohm\(^{-1}\) cm\(^{2}\)
• D. 222.4 Ohm\(^{-1}\) cm\(^{2}\)

Hint:

Equivalent conductance is dependent on the ions in the electrolyte, and similar electrolytes will have similar conductance values.

Answer 1

The Correct Option is A

Step 1: Understand equivalent conductance. The equivalent conductance of an electrolyte is a function of the ions present and their mobility. Since NaF and KF are similar in nature, their equivalent conductance will remain the same.
Step 2: Conclusion. Thus, the equivalent conductance for KF is 90.1 Ohm\(^{-1}\) cm\(^{2}\), the same as NaF.