2, 8, 2 and 2, 8, 7
To determine the electronic configurations of Mg+2 and Cl– ions, we start by understanding their neutral atoms:
1. Magnesium (Mg): A neutral magnesium atom has an atomic number of 12, so its electronic configuration is 2, 8, 2. When it loses 2 electrons to form Mg+2, it loses its two outermost electrons, resulting in the configuration 2, 8.
2. Chlorine (Cl): A neutral chlorine atom has an atomic number of 17, making its electronic configuration 2, 8, 7. When it gains one electron to become Cl–, it adds one electron to its outer shell, resulting in the configuration 2, 8, 8.
Hence, the electronic configurations of Mg+2 and Cl– ions are 2, 8 and 2, 8, 8, respectively.
Explanation:
Correct Answer: 2, 8 and 2, 8, 8
If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]