2, 8, 2 and 2, 8, 7
To determine the electronic configurations of Mg+2 and Cl– ions, we start by understanding their neutral atoms:
1. Magnesium (Mg): A neutral magnesium atom has an atomic number of 12, so its electronic configuration is 2, 8, 2. When it loses 2 electrons to form Mg+2, it loses its two outermost electrons, resulting in the configuration 2, 8.
2. Chlorine (Cl): A neutral chlorine atom has an atomic number of 17, making its electronic configuration 2, 8, 7. When it gains one electron to become Cl–, it adds one electron to its outer shell, resulting in the configuration 2, 8, 8.
Hence, the electronic configurations of Mg+2 and Cl– ions are 2, 8 and 2, 8, 8, respectively.
Explanation:
Correct Answer: 2, 8 and 2, 8, 8
Standard electrode potential for \( \text{Sn}^{4+}/\text{Sn}^{2+} \) couple is +0.15 V and that for the \( \text{Cr}^{3+}/\text{Cr} \) couple is -0.74 V. The two couples in their standard states are connected to make a cell. The cell potential will be:
To calculate the cell potential (\( E^\circ_{\text{cell}} \)), we use the standard electrode potentials of the given redox couples.
Given data:
\( E^\circ_{\text{Sn}^{4+}/\text{Sn}^{2+}} = +0.15V \)
\( E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74V \)