2, 8, 2 and 2, 8, 7
To determine the electronic configurations of Mg+2 and Cl– ions, we start by understanding their neutral atoms:
1. Magnesium (Mg): A neutral magnesium atom has an atomic number of 12, so its electronic configuration is 2, 8, 2. When it loses 2 electrons to form Mg+2, it loses its two outermost electrons, resulting in the configuration 2, 8.
2. Chlorine (Cl): A neutral chlorine atom has an atomic number of 17, making its electronic configuration 2, 8, 7. When it gains one electron to become Cl–, it adds one electron to its outer shell, resulting in the configuration 2, 8, 8.
Hence, the electronic configurations of Mg+2 and Cl– ions are 2, 8 and 2, 8, 8, respectively.
Explanation:
Correct Answer: 2, 8 and 2, 8, 8


Electricity is passed through an acidic solution of Cu$^{2+}$ till all the Cu$^{2+}$ was exhausted, leading to the deposition of 300 mg of Cu metal. However, a current of 600 mA was continued to pass through the same solution for another 28 minutes by keeping the total volume of the solution fixed at 200 mL. The total volume of oxygen evolved at STP during the entire process is ___ mL. (Nearest integer)
Given:
$\mathrm{Cu^{2+} + 2e^- \rightarrow Cu(s)}$
$\mathrm{O_2 + 4H^+ + 4e^- \rightarrow 2H_2O}$
Faraday constant = 96500 C mol$^{-1}$
Molar volume at STP = 22.4 L