Question:
\( E=^0_{cr^{3+}/cr}=-0.72 V, E^0_{fe^{2+}/fe}=-0.42\) The potential for the cell Cr|Cr3+(0.1 M) || Fe2+(o.01 M) Fe is
\( E=^0_{cr^{3+}/cr}=-0.72 V, E^0_{fe^{2+}/fe}=-0.42\) The potential for the cell Cr|Cr3+(0.1 M) || Fe2+(o.01 M) Fe is
Updated On: Jun 25, 2024
- -0.339 V
- -0.26 V
- 0.26 V
- 0.3 V
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The Correct Option is C
Solution and Explanation
The correct option is (C): 0.26 V
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