The given differential equation is:
\(\frac {dy}{dx} =\sqrt {4-y^2}\)
Separating the variables, we get:
\(\frac {dy}{\sqrt {4-y^2}} =dx\)
Now, integrating both sides of both sides, we get:
\(∫\frac {dy}{\sqrt {4-y^2}} =∫dx\)
\(⇒sin^{-1}\frac y2=x+C\)
\(⇒\frac y2=sin(x+C)\)
\(⇒y=2sin(x+C)\)
This is the required general solution of the given differential equation.

A ladder of fixed length \( h \) is to be placed along the wall such that it is free to move along the height of the wall.
Based upon the above information, answer the following questions:
(iii) (b) If the foot of the ladder, whose length is 5 m, is being pulled towards the wall such that the rate of decrease of distance \( y \) is \( 2 \, \text{m/s} \), then at what rate is the height on the wall \( x \) increasing when the foot of the ladder is 3 m away from the wall?
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely