Number of apples | 1 | 2 | 3 | 4 | 5 |
Cost(In Rs) | 5 | 10 | 15 | 20 | 25 |
(b) Distance travelled by a car
Time (In hours) | 6 a.m | 7 a.m | 8 a.m | 9 a.m |
Distance (In km) | 40 | 80 | 120 | 160 |
(i) How much distance did the car cover during the period 7.30 a.m. to 8 a.m.?
(ii) What was the time when the car had covered a distance of 100 km since its start?
(c) Interest on deposits for a year.
Deposit | 1000 | 2000 | 3000 | 4000 | 5000 |
Simple Interest (in Rs) | 80 | 160 | 240 | 320 | 400 |
(i) Does the graph pass through the origin?
(ii) Use the graph to find the interest on 2500 for a year.
(iii) To get an interest of 280 per year, how much money should be deposited?
(a) Taking a suitable scale (for \(x-axis\), \(1\) unit = \(1\) apple and for \(y-axis\), 1 unit = Rs \(5\)),
we can mark the number of apples on \(x-axis\) and the cost of apples on \(y-axis\).
A graph of the given data is as follows.
(b) Taking a suitable scale (for \(x-axis\), \(2\) units = \(1\) hour and for \(y-axis\), \(2\) units = \(40\) \(km\)),
we can represent the time on \(x-axis\) and the distance covered by the car on \(y-axis\).
A graph of the given data is as follows.
(i) During the period \(7:30\) a.m. to \(8\) a.m., the car covered a distance of \(20\) \(km\).
(ii) The car covered a distance of \(100\) \(km\) at \(7:30\) a.m. since its start.
(c) Taking a suitable scale,
For \(x-axis\), \(1\) unit = Rs \(1000\) and for \(y-axis\), \(1\) unit = Rs \(80\)
We can represent the deposit on \(x-axis\) and the interest earned on that deposit on \(y-axis\).
A graph of the given data is obtained as follows.
From the graph, the following points can be observed.