What is the time complexity of the following algorithm?
int func(int n) {
for (int i = 1; i < = n; i++) {
for (int j = 1; j < = n; j++) {
printf("Hello");
}
}
}
To determine the time complexity of an algorithm, consider the number of iterations of each loop. The time complexity for nested loops is the product of the iterations.
O(n)
O(n²)
O(n³)
O(log n)
Understanding the Algorithm
- The outer loop runs n times.
- The inner loop also runs n times for each iteration of the outer loop.
- The total number of executions of the `printf` statement is \( n \times n = n^2 \).
Thus, the time complexity of the algorithm is O(n²).
Match the following layers with their corresponding functionalities:
\[ \begin{array}{|c|c|} \hline \textbf{Layer} & \textbf{Functionality} \\ \hline \text{Networking Layer} & \text{Data packet transfer} \\ \text{Transport Layer} & \text{Host-to-host communication} \\ \text{Data Link Layer} & \text{Error detection and correction} \\ \hline \end{array} \]Let \( A \) be a \( 3 \times 3 \) matrix defined as:
\[ A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & -1 \end{bmatrix} \]Find the eigenvalues of \( A^{13} \).
Consider the following process information for Shortest Remaining Time First (SRTF) scheduling:
\[ \begin{array}{|c|c|c|} \hline \textbf{Process} & \textbf{Arrival Time (AT)} & \textbf{Burst Time (BT)} \\ \hline P1 & 0 & 10 \\ P2 & 1 & 13 \\ P3 & 2 & 6 \\ P4 & 8 & 9 \\ \hline \end{array} \]Find the turnaround time for each process.
Given the following cache parameters:
\[ \begin{array}{|c|c|} \hline \textbf{Tag} & 4 \, \text{bits} \\ \textbf{Index} & 12 \, \text{bits} \\ \textbf{Block Size} & 1 \, \text{byte} \\ \hline \end{array} \]Find the size of the main memory and the size of the cache memory.
Consider the following code:
main() { int x = 126, y = 105; { if (x > y) x = x - y; else y = y - x; } while (x != y) printf("%d", x); }
Consider the following code:
int a; int arr[] = {30, 50, 10}; int *ptr = arr[10] + 1; a = *ptr; (*ptr)++; ptr = ptr + 1; printf("%d", a + arr[1] + *ptr);
What is the output of the following C code?
void foo(int *p, int x) { *p = x; } void main() { int *z; int a = 20, b = 25; z = a; // Incorrect: Should be z = a; foo(z, b); printf("%d", a); }
Issue: The statement z = a;
is invalid because a
is an integer, and z
is a pointer.
Find the signed binary expansion of the number -6.
Which of the following is the greatest? \[ 0.6, \ 0.666, \ \frac{5}{6}, \ \frac{2}{3} \]
Given the following information:
The logical address (L.A.) is 32 bits. The physical address (P.A.) is 20 bits. The page size (P.S.) is 2048 bytes (2 KB). What is the maximum number of entries in the page table?