\((i) [Fe(CN)_6]^{4-}\)
In the above coordination complex, iron exists in the +II oxidation state.
\(Fe^{ 2+}\) : Electronic configuration is \(3d ^{6} \)
Orbitals of \(Fe^{ 2+}\) ion:

Hence, the geometry of the complex is octahedral and the complex is diamagnetic (as there are no unpaired electrons).
\((ii) [FeF_6]^{ 3-} \)
In this complex, the oxidation state of Fe is +3.
Orbitals of \(Fe^{+3}\) ion: 
\((iii) [Co(C_2O_4)_3]^{ 3-}\)
Cobalt exists in the +3 oxidation state in the given complex
Orbitals of \(Co ^{3+}\) ion: 
\((iv) [CoF_6]^{ 3-}\)
Cobalt exists in the \(+3 \) oxidation state.
Orbitals of \(Co^{3+}\) ion: 
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is:
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
What is crystal field splitting energy?
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H$_2$O)$_6$]Cl$_3$ complex is coloured? What happens on heating the complex [Ti(H$_2$O)$_6$]Cl$_3$? Give reason.
There are three applications of coordination compounds: