Assume the speed of train be \(x\ \frac{km}{hr}\)
Assume the speed of car be \(y\ \frac{km}{hr}\)
From the question, we know that
= \(\frac{160}{x} + \frac{600}{y} = 8\) – equation (i)
= \(\frac{240}{x} + \frac{520}{y} = 8 + \frac{12}{60} = 8.2\) – equation (ii)
Multiplying equation (i) by 3 and equation (ii) by 2 we get,
\(\frac{1800}{y} - \frac{1040}{y} = 24 - 16.4\)
\(\frac{720}{y} = 7.6\)
\(y = \frac{760}{7.6}\)
= 100
\(x = \frac{160}{2} = 80\)
So, the speed of train is \(80\ \frac{km}{hr}\)
the speed of car is\(100\ \frac{km}{hr}\)
The correct option is (A): 80 km/hr, 100 km/hr