Question

Dimensions of kinematic viscosity is

• A. \( MLT^{-1} \)
• B. \( L^2T^{-1} \)
• C. \( L^2T \)
• D. \( L^2T^2 \)

Hint:

Kinematic viscosity has dimensions of area per unit time.

Answer 1

The Correct Option is B

Kinematic viscosity \( \nu \) is defined as the ratio of dynamic viscosity \( \mu \) to density \( \rho \):
\[ \nu = \frac{\mu}{\rho} \]
\[ [\mu] = \frac{ML^{-1}T^{-1}}{ML^{-3}} = L^2T^{-1} \]