Question:

Differentiate the following w.r.t. x: log(cos ex)

Updated On: Oct 11, 2023
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Solution and Explanation

Let y=log(cos ex)

By using the chain rule, we obtain

\(\frac{dy}{dx}=\frac{d}{dx}[log(cos e^x]\)

=\(\frac{1}{cose^x}.\frac{d}{dx}(cose^x)\)

=\(\frac{1}{cose^x}.(-sin e^x).\frac{d}{dx}(e^x)\)

=\(\frac{-sin e^x}{cos e^x}.e^x\)

=-\(e^x tan e^x,e^x\)\((2n+1)\frac{\pi}{2},\)\(nεN\)

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