What would be the voltage of this cell? (Eo cell = 0.46 V)
(a.) Molar conductivity is the conductivity of a solution, which contains a given number of moles of solute in 1L. The symbol for molar conductivity is lambda and the SI unit is Sm²mol⁻¹. It behaves differently for both weak and strong electrolytes.
Strong: Molar conductivity increases linearly with the square root of the concentration. But eventually reaches a limiting value ( limiting molar conductivity) at very high concentration.
Weak: Molar conductivity increases but it is less significant as compared to strong electrolyte. At lower concentration the increase in conductivity is linear and significant.
(b.) Ecell = E°cell - \(\frac{0.059}{n}\) log \(\frac{[Cu 2^{+}]}{[Ag^{+}]^{2}}\)
According to the question, Ecell = 0.46V, n=2, [Cu2+] = 0.1M, [Ag+] = 0.001M
Substituting the values,
\(E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log \frac{0.1}{(10^{-3})^{2}}\)
\(E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log 10^{5}\)
\(E_{cell}=0.46 - \frac{0.0591}{2} \times 5log 10\)
\(E_{cell}=0.46 - 0.14775\)
\(E_{cell}=0.312V\)


Electricity is passed through an acidic solution of Cu$^{2+}$ till all the Cu$^{2+}$ was exhausted, leading to the deposition of 300 mg of Cu metal. However, a current of 600 mA was continued to pass through the same solution for another 28 minutes by keeping the total volume of the solution fixed at 200 mL. The total volume of oxygen evolved at STP during the entire process is ___ mL. (Nearest integer)
Given:
$\mathrm{Cu^{2+} + 2e^- \rightarrow Cu(s)}$
$\mathrm{O_2 + 4H^+ + 4e^- \rightarrow 2H_2O}$
Faraday constant = 96500 C mol$^{-1}$
Molar volume at STP = 22.4 L