What would be the voltage of this cell? (Eo cell = 0.46 V)
(a.) Molar conductivity is the conductivity of a solution, which contains a given number of moles of solute in 1L. The symbol for molar conductivity is lambda and the SI unit is Sm²mol⁻¹. It behaves differently for both weak and strong electrolytes.
Strong: Molar conductivity increases linearly with the square root of the concentration. But eventually reaches a limiting value ( limiting molar conductivity) at very high concentration.
Weak: Molar conductivity increases but it is less significant as compared to strong electrolyte. At lower concentration the increase in conductivity is linear and significant.
(b.) Ecell = E°cell - \(\frac{0.059}{n}\) log \(\frac{[Cu 2^{+}]}{[Ag^{+}]^{2}}\)
According to the question, Ecell = 0.46V, n=2, [Cu2+] = 0.1M, [Ag+] = 0.001M
Substituting the values,
\(E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log \frac{0.1}{(10^{-3})^{2}}\)
\(E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log 10^{5}\)
\(E_{cell}=0.46 - \frac{0.0591}{2} \times 5log 10\)
\(E_{cell}=0.46 - 0.14775\)
\(E_{cell}=0.312V\)
List-I (Symbol of electrical property) | List-II (Units) |
---|---|
A) \( \Omega \) | I) S cm\(^{-1}\) |
B) G | II) m\(^{-1}\) |
C) \( \kappa \) | III) S cm\(^2\) mol\(^{-1}\) |
D) G\(^*\) | IV) S |