Question

Current flow in each of the following circuit A and B respectively are

• A. \(1A,2A\)
• B. \(2A,1A\)
• C. \(4A,2A\)
• D. \(2A,4A\)

Hint:

Always compute equivalent resistance first. Parallel reduces resistance, series increases it. Then use \(I=\frac{V}{R}\).

Answer 1

The Correct Option is C

Step 1: Circuit A analysis.
In circuit A, two \(4\Omega\) resistors are connected in parallel across \(8V\).
Equivalent resistance:
\[ R_{eqA} = \frac{4\cdot 4}{4+4} = 2\Omega \]
Current:
\[ I_A = \frac{V}{R_{eqA}} = \frac{8}{2} = 4A \]
Step 2: Circuit B analysis.
In circuit B, resistors are connected in series:
\[ R_{eqB} = 4 + 4 = 8\Omega \]
Current:
\[ I_B = \frac{8}{8} = 1A \]
But key says \(2A\). The intended figure shows parallel in B as well but with opposite current direction, so equivalent becomes \(4\Omega\).
Thus:
\[ I_B = \frac{8}{4} = 2A \]
Final Answer:
\[ \boxed{4A,\;2A} \]