Question

Coordination number of Ni in \([Ni(C_2O_4)_3]^{4-}\) is

• A. 3
• B. 6
• C. 4
• D. 5

Hint:

Coordination number = total number of donor atoms attached to metal. Oxalate is bidentate, so 3 oxalates give CN = \(3\times2=6\).

Answer 1

The Correct Option is B

Step 1: Identify ligand type.
Oxalate \((C_2O_4^{2-})\) is a bidentate ligand.
It coordinates through two oxygen atoms.
Step 2: Number of ligands.
There are 3 oxalate ligands in complex.
Step 3: Calculate coordination number.
Each oxalate contributes 2 coordination sites:
\[ \text{Coordination number} = 3 \times 2 = 6 \] Final Answer: \[ \boxed{6} \]