Convert the following:
i. Ethyl alcohol into ethyl acetate
ii. Phenol into benzene
iii. Diethyl ether into ethyl chloride
i. Ethyl Alcohol to Ethyl Acetate:
CH3CH2OH + CH3COOH ⟶H2SO4, heat CH3COOCH2CH3 + H2O
Explanation: Ethyl alcohol reacts with acetic acid in the presence of concentrated sulphuric acid and heat to form ethyl acetate (an ester) and water. This reaction is known as **esterification**.
ii. Phenol to Benzene:
C6H5OH ⟶Zn dust, heat C6H6 + ZnO
Explanation: When phenol is heated with zinc dust, it undergoes reduction. The –OH group is removed as ZnO and the product formed is **benzene**.
iii. Diethyl Ether to Ethyl Chloride:
(C2H5)2O + 2HCl ⟶ZnCl2, heat 2C2H5Cl + H2O
Explanation: Diethyl ether reacts with concentrated hydrochloric acid in the presence of anhydrous zinc chloride upon heating to form **ethyl chloride** and water. This is an example of **cleavage of ether** by halogen acids.
Topic: Alcohols, Phenols, and Ethers — Conversion Reactions
Given below are two statements:
Statement I: Dimethyl ether is completely soluble in water. However, diethyl ether is soluble in water to a very small extent.
Statement II: Sodium metal can be used to dry diethyl ether and not ethyl alcohol.
In the light of the given statements, choose the correct answer from the options given below: