Question:
Consider two coherent point sources \( S_1 \) and \( S_2 \) separated by a small distance along a vertical line and two screens \( P_1 \) and \( P_2 \) placed as shown in the figure. Which one of the choices represents the shapes of the interference fringes at the central regions on the screens?
Consider two coherent point sources \( S_1 \) and \( S_2 \) separated by a small distance along a vertical line and two screens \( P_1 \) and \( P_2 \) placed as shown in the figure. Which one of the choices represents the shapes of the interference fringes at the central regions on the screens?
Show Hint
For two point sources, the interference pattern on a screen depends on the relative positions of the sources and the screen. Circular patterns are observed when the sources are symmetrically placed.
Updated On: Nov 18, 2025
- Circular on \( P_1 \) and straight lines on \( P_2 \).
- Circular on \( P_1 \) and circular on \( P_2 \).
- Straight lines on \( P_1 \) and straight lines on \( P_2 \).
- Straight lines on \( P_1 \) and circular on \( P_2 \).
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understanding the interference pattern.
When two coherent point sources are placed in close proximity, the interference pattern observed on the screen depends on the geometry of the setup. The interference fringes on the screen \( P_1 \) will be circular due to the circular symmetry of the sources, while the pattern on \( P_2 \) will form straight lines due to the linear arrangement of the sources.
Step 2: Conclusion.
Thus, the correct answer is option (A).
When two coherent point sources are placed in close proximity, the interference pattern observed on the screen depends on the geometry of the setup. The interference fringes on the screen \( P_1 \) will be circular due to the circular symmetry of the sources, while the pattern on \( P_2 \) will form straight lines due to the linear arrangement of the sources.
Step 2: Conclusion.
Thus, the correct answer is option (A).
Was this answer helpful?
0
0
Top Questions on Physics
Match List I with List II :
List I List II (A) Electrical Energy into mechanical energy (III) Electric motor (B) Electrical Energy into Light energy (II) Tube light (C) Mechanical Energy into Electrical Energy (I) Dynamo (D) Solar energy into electrical energy (IV) Solar cell Choose the correct answer from the options given below :
Match List I with List II :
List I List II (A) Temperature (III) Kelvin (K) (B) Mass (I) Kilogram (kg) (C) Electric current (IV) Ampere (A) (D) Length (II) Meter (m) Choose the correct answer from the options given below :
- The blue colour of sky is due to
- Arrange the following in increasing order of their wavelength.
A. gamma radiations
B. X rays
C. UV radiations
D. microwave
E. Infrared radiations - Kinematics deal with the
View More Questions
Questions Asked in IIT JAM exam
- Consider a volume V enclosed by a closed surface S having unit surface normal \(\hat{n}\). For \(\mathbf{r} = x\hat{i} + y\hat{j} + z\hat{k}\), the value of the surface integral \(\frac{1}{9} \oint_{S} \mathbf{r} \cdot \hat{n} \,dS\) is
- IIT JAM PH - 2025
- Vector Calculus
- For a Zener diode as shown in the circuit diagram below, the Zener voltage \(V_Z\) is 3.7 V. For a load resistance (\(R_L\)) of 1 k\(\Omega\), a current \(I_1\) flows through the load. If \(R_L\) is decreased to 500 \(\Omega\), the current changes to \(I_2\). The ratio \(\frac{I_2}{I_1}\) is \rule{1cm{0.15mm}. (up to two decimal places)}
- IIT JAM PH - 2025
- Analog Electronics
- The shortest distance between an object and its real image formed by a thin convex lens of focal length 20 cm is _____ cm. (in integer)
- If \(\left(\frac{1-i}{1+i}\right)^{n/2} = -1\), where \(i = \sqrt{-1}\), one possible value of n is
- IIT JAM PH - 2025
- Complex numbers
- In a two-level atomic system, the excited state is 0.2 eV above the ground state. Considering the Maxwell-Boltzmann distribution, the temperature at which 2% of the atoms will be in the excited state is _____ K. (up to two decimal places)
(Boltzmann constant \(k_B = 8.62 \times 10^{-5}\) eV/K)
- IIT JAM PH - 2025
- Mechanics
View More Questions