Question:

Consider the queues \(Q_1\) containing four elements and \(Q_2\) containing none (shown as the Initial State in the figure). The only operations allowed on these two queues are Enqueue(\(Q\), element) and Dequeue(\(Q\)). The minimum number of Enqueue operations on \(Q_1\) required to place the elements of \(Q_1\) in \(Q_2\) in reverse order (shown as the Final State in the figure) without using any additional storage is 
 

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To reverse the order of elements between two queues, dequeue from one and enqueue to the other. The minimum number of operations is based on how many items need to be moved.
Updated On: Jan 30, 2026
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Solution and Explanation

Initially, \(Q_1 = [1, 2, 3, 4]\) and \(Q_2 = []\).

To reverse the elements of \(Q_1\) using \(Q_2\) with the minimum number of Enqueue operations, we perform the following steps:

1. Dequeue element 1 from \(Q_1\) and Enqueue it to \(Q_2\). \(Q_1 = [2, 3, 4]\), \(Q_2 = [1]\)

2. Dequeue element 2 from \(Q_1\) and Enqueue it to \(Q_2\). \(Q_1 = [3, 4]\), \(Q_2 = [1, 2]\)

3. Dequeue element 3 from \(Q_1\) and Enqueue it to \(Q_2\). \(Q_1 = [4]\), \(Q_2 = [1, 2, 3]\)

4. Dequeue element 4 from \(Q_1\) and Enqueue it to \(Q_2\). \(Q_1 = []\), \(Q_2 = [1, 2, 3, 4]\)

The elements are now in reverse order in \(Q_2\), so the minimum number of Enqueue operations on \(Q_1\) is: \[ \boxed{0} \]
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