Question:

Consider the following three functions:
\[ f_1 = 10^n, f_2 = n^{\log n}, f_3 = n^{\sqrt{n}} \] Which one of the following options arranges the functions in the increasing order of asymptotic growth rate?

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To compare fast-growing functions, convert them into exponential form and compare exponents.
Updated On: Jan 30, 2026
  • \( f_3, f_2, f_1 \)
  • \( f_2, f_1, f_3 \)
  • \( f_1, f_2, f_3 \)
  • \( f_2, f_3, f_1 \)
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The Correct Option is D

Solution and Explanation

Step 1: Rewrite functions in exponential form.
We rewrite each function using exponentials to compare growth rates:
\[ f_2 = n^{\log n} = e^{(\log n)^2}, f_3 = n^{\sqrt{n}} = e^{\sqrt{n}\log n}, f_1 = 10^n = e^{n\log 10}. \]

Step 2: Compare exponents.
\[ (\log n)^2 \ll \sqrt{n}\log n \ll n. \] Hence, \( f_2 \) grows slower than \( f_3 \), and \( f_3 \) grows slower than \( f_1 \).

Step 3: Arrange in increasing order.
\[ f_2 < f_3 < f_1. \]

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