\( z \) gives a yellow precipitate of \( \text{CHI}_3 \) with NaOH + \( \text{I}_2 \) solution.
\( z \) gives isopropyl alcohol on reduction with \( \text{H}_2 \) in the presence of Pd catalyst.
\( z \) on reaction with \( \text{CH}_3\text{MgBr} \) followed by hydrolysis gives \( 2^\circ \) alcohol.
\( z \) does not give positive test with Fehling’s reagent
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The Correct Option isA
Solution and Explanation
Step 1: Reaction pathway
Isopropyl benzene (cumene) on oxidation gives cumene hydroperoxide, which upon acid hydrolysis gives acetophenone:
\[
\text{(CH}_3)_2CH{-}C_6H_5 \xrightarrow{O_2} \text{Cumene hydroperoxide} \xrightarrow{H^+} \text{Acetophenone}
\]
Step 2: Structure of \( z \)
\[
z = \text{Acetophenone } (C_6H_5COCH_3)
\]
Step 3: Analyze each option
\begin{itemize}
\item[1.] Acetophenone does not give iodoform test (requires a methyl ketone attached to an aliphatic group, not aromatic) → Incorrect
\item[2.] Acetophenone on catalytic hydrogenation gives isopropyl benzene → Correct
\item[3.] Reaction with CH\textsubscript{3}MgBr gives tertiary alcohol → Correct
\item[4.] Acetophenone is a ketone; it does not respond to Fehling’s test → Correct
\end{itemize}
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