Question

Consider the following reactions: \[ \text{NaCl} + \text{K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 (\text{Conc.}) \rightarrow (A) + \text{Side products} \] \[ (B) + \text{H}_2\text{SO}_4 (\text{dilute}) + \text{H}_2\text{O}_2 \rightarrow (C) + \text{Side products} \] The sum of the total number of atoms in one molecule each of (A), (B) and (C) is __________.

• A. 18
• B. 15
• C. 21
• D. 20

Hint:

To calculate the total number of atoms, carefully balance the chemical equation and count the atoms on both sides of the reaction.

Answer 1

The Correct Option is A

Step 1: Analyze the reactions.
We are given two reactions. To calculate the total number of atoms, we need to balance the elements in the reactants and products.

Step 2: Calculate the total number of atoms.
In one molecule of each compound (A), (B), and (C), we calculate the sum of the atoms involved. The total comes out to be 18.