Question:
Consider the following reaction:
Consider the following reaction:
Show Hint
When analyzing reactions, understand the role of conditions and catalysts in directing product formation.
Updated On: Jan 6, 2026
- \( \text{li} \) is the correct label for the reaction.
- The structure is based on certain conditions.
- Possible outcome in higher reaction scenarios.
- None of these is relevant.
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Analyzing the reaction.
This reaction involves a conditional situation based on structure and variable outcomes in the reaction system. Conditions for a reaction are discussed.
Step 2: Conclusion.
Option (2) describes the correct outcome, i.e., the structure is based on specific conditions.
Was this answer helpful?
0
0
Top Questions on Chemical Kinetics
- Correct statements regarding Arrhenius equation among the following are:
Factor \(e^{-E_a/RT}\) corresponds to fraction of molecules having kinetic energy less than \(E_a\).
At a given temperature, lower the \(E_a\), faster is the reaction.
Increase in temperature by about \(10^\circ\text{C}\) doubles the rate of reaction.
Plot of \(\log k\) vs \(\dfrac{1}{T}\) gives a straight line with slope \(= -\dfrac{E_a}{R}\).
Choose the correct answer from the options given below:- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- Decomposition of A is a first order reaction at T(K) and is given by \( A(g) \rightarrow B(g) + C(g) \).
In a closed 1 L vessel, 1 bar A(g) is allowed to decompose at T(K). After 100 minutes, the total pressure was 1.5 bar. What is the rate constant (in \( min^{-1} \)) of the reaction ? (\( \log 2 = 0.3 \))- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- An organic compound undergoes first order decomposition. The time taken for decomposition to \(\dfrac{1}{8}\) and \(\dfrac{1}{10}\) of its initial concentration are \(t_{1/8}\) and \(t_{1/10}\) respectively. Find the value of \[ \frac{t_{1/8}}{t_{1/10}}\times10 \] (Given: \(\log 2 = 0.3\))
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
Consider the following compounds. Arrange these compounds in a n increasing order of reactivity with nitrating mixture. The correct order is :
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- At $27^\circ\text{C}$, in presence of a catalyst, activation energy of a reaction is lowered by $10\,\text{kJ mol}^{-1}$. The logarithm of the ratio $\dfrac{k(\text{catalysed})}{k(\text{uncatalysed})}$ is ___.
(Consider that the frequency factor for both the reactions is same)
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
View More Questions
Questions Asked in VITEEE exam
- Find the value of \( x \) in the following equation: \[ \frac{2}{x} + \frac{3}{x + 1} = 1 \]
- VITEEE - 2025
- Algebra
- How many numbers between 0 and 9 look the same when observed in a mirror?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Data Interpretation
- TUV : VYB :: PRA : ?
- VITEEE - 2025
- Odd one Out
View More Questions