Question:

Consider the following carbocations : I. $Cl_3 \overset{+}C$ II. $Cl_{2} \overset{+} {C}H$ III. $Cl \overset{+} {C}H_{2}$ IV. $ \overset{+} {C}H_{3}$ The stability sequence follows the order

Updated On: Jun 23, 2023
  • IV < I < III < II
  • I < II < III < IV
  • II < III < IV < I
  • III < I < II < IV
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The Correct Option is B

Solution and Explanation

Electron withdrawing groups like $?NO_2$, $? X$ etc., decrease the stability of carbonium ion. So, the stability order is $Cl_3C^+ < Cl_2$$\overset{+}{C}H < Cl \overset{+}{C}H_2 < \overset{+}{C}H_3$
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