Question:
Consider the following C program. Assume parameters to a function are evaluated from right to left.}
\begin{verbatim}
#include stdio.h
int g(int p) { printf("%d", p); return p; }
int h(int q) { printf("%d", q); return q; }
void f(int x, int y) {
g(x);
h(y);
}
int main() {
f(g(10), h(20));
}
\end{verbatim}
Which one of the following options is the CORRECT output of the above C program?
Consider the following C program. Assume parameters to a function are evaluated from right to left.}
\begin{verbatim}
#include stdio.h
int g(int p) { printf("%d", p); return p; }
int h(int q) { printf("%d", q); return q; }
void f(int x, int y) {
g(x);
h(y);
}
int main() {
f(g(10), h(20));
}
\end{verbatim}
Which one of the following options is the CORRECT output of the above C program?
Show Hint
When function parameters are evaluated right to left}, start with the last parameter, and carefully track the order of execution and the sequence of prints.
Updated On: Jan 23, 2025
- 20101020
- 10202010
- 20102010
- 10201020
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The Correct Option is A
Solution and Explanation
The execution of the given C program proceeds as follows:
In the \texttt{main()} function, the function \texttt{f(g(10), h(20))} is called.
Parameters to the function \texttt{f()} are evaluated from right to left.
\texttt{h(20)} is evaluated first, printing \(20\) and returning \(20\).
\texttt{g(10)} is evaluated next, printing \(10\) and returning \(10\).
Therefore, the first part of the output is \(20\) followed by \(10\).
The function \texttt{f()} is then executed:
\texttt{g(x)} is called with \(x = 10\), printing \(10\).
\texttt{h(y)} is called with \(y = 20\), printing \(20\).
The second part of the output is \(10\) followed by \(20\).
Combining these parts, the total output is: \[ 20101020 \] Final Answer: \[ \boxed{20101020} \]
In the \texttt{main()} function, the function \texttt{f(g(10), h(20))} is called.
Parameters to the function \texttt{f()} are evaluated from right to left.
\texttt{h(20)} is evaluated first, printing \(20\) and returning \(20\).
\texttt{g(10)} is evaluated next, printing \(10\) and returning \(10\).
Therefore, the first part of the output is \(20\) followed by \(10\).
The function \texttt{f()} is then executed:
\texttt{g(x)} is called with \(x = 10\), printing \(10\).
\texttt{h(y)} is called with \(y = 20\), printing \(20\).
The second part of the output is \(10\) followed by \(20\).
Combining these parts, the total output is: \[ 20101020 \] Final Answer: \[ \boxed{20101020} \]
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