Consider the crystal structure shown in the figure, where black and grey spheres represent atoms of two different elements and \(a\) denotes the lattice constant. The Bravais lattice for this structure is: 
Step 1: Observe the structure.
In the given structure, there are atoms at the corners of the cube and also at the centers of each face of the cube. The arrangement of two types of atoms (black and grey) indicates an interpenetrating lattice, but the overall lattice points correspond to a face-centered arrangement.
Step 2: Identify the Bravais lattice.
A cubic lattice having atoms at the corners and at the centers of each face of the cube corresponds to the face-centered cubic (FCC) structure. Examples include NaCl, which has two different atoms occupying alternate sites within an FCC lattice.
Step 3: Conclusion.
Hence, the Bravais lattice of the given crystal is Face-centered cubic.

At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)