To determine the values of \( a \) and \( b \) for which the given force field is conservative, we start by recalling that for a two-dimensional vector field \(\overrightarrow{F}(x, y) = P(x, y) \hat{x} + Q(x, y) \hat{y}\), to be conservative, it must satisfy:
\(\frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}\)
Given the force field:
\(\overrightarrow{F}(x,y) = (5x^2 + ay^2 + bxy)\hat{x} + (4x^2 + 4xy + y^2) \hat{y}\)
Here, \( P(x, y) = 5x^2 + ay^2 + bxy \) and \( Q(x, y) = 4x^2 + 4xy + y^2 \).
Conclusion: The correct answer is \(a = 2\) and \(b = 8\), which is supported by the examination of partial derivatives to confirm conservativeness of the force field.
In order to achieve the static equilibrium of the see-saw about the fulcrum \( P \), shown in the figure, the weight of Box B should be _________ kg, if the weight of Box A is 50 kg.

A particle of mass 1kg, initially at rest, starts sliding down from the top of a frictionless inclined plane of angle \(\frac{𝜋}{6}\)\(\frac{\pi}{6}\) (as schematically shown in the figure). The magnitude of the torque on the particle about the point O after a time 2seconds is ______N-m. (Rounded off to nearest integer) 
(Take g = 10m/s2)

