Question

Consider a granulite facies metamorphic rock with peak metamorphic condition at 9 kbar, 850°C. Assume a single layer crust of \(\rho = 3000 \, \text{kg/m}^3\) and \(g = 10 \, \text{m/sec}^2\) during metamorphism. The depth of burial during peak metamorphism is (give answer in kilometers).

Hint:

The depth of burial can be calculated using pressure, density, and gravitational acceleration. Ensure the units are consistent for correct calculation.

Answer 1

Step 1: Understanding the question.
The question asks for the depth of burial during peak metamorphism based on the pressure (in kbar), density, and gravitational acceleration.
Step 2: Analyzing the solution.
The depth of burial (D) can be calculated using the formula: \[ P = \rho g D \] Where \(P\) is the pressure, \(\rho\) is the density, and \(g\) is the gravitational acceleration. Rewriting the equation for depth: \[ D = \frac{P}{\rho g} \] Substitute the given values: \[ D = \frac{9 \times 10^3}{3000 \times 10} = 30.0 \, \text{km} \] Step 3: Conclusion.
The correct answer is 30.0 km, the depth of burial during peak metamorphism.