The first equation represents the reduction of permanganate ions (\( \text{MnO}_4^- \)) in acidic medium. The balanced equation is:
\[
3 \text{MnO}_4^- + 4 \text{H}^+ \longrightarrow 2 \text{MnO}_4^- + \text{MnO}_2 + 2 \text{H}_2\text{O}
\]
Explanation:
- Permanganate (\( \text{MnO}_4^- \)) is reduced to manganese dioxide (\( \text{MnO}_2 \)) in acidic medium.
- The oxidation state of manganese in \( \text{MnO}_4^- \) is +7, and it is reduced to +4 in \( \text{MnO}_2 \), releasing oxygen and water.
(b) The second equation represents the reaction of dichromate ions (\( \text{Cr}_2 \text{O}_7^{2-} \)) in acidic medium, where it is reduced by \( \text{Fe}^{2+} \) to form \( \text{Cr}^{3+} \) ions. The balanced equation is:
\[
\text{Cr}_2 \text{O}_7^{2-} + 14 \text{H}^+ + 6 \text{Fe}^{2+} \longrightarrow 2 \text{Cr}^{3+} + 6 \text{Fe}^{3+} + 7 \text{H}_2\text{O}
\]
Explanation:
- Dichromate (\( \text{Cr}_2 \text{O}_7^{2-} \)) is reduced to \( \text{Cr}^{3+} \) in the presence of acidic conditions.
- The iron (\( \text{Fe}^{2+} \)) acts as a reducing agent and is oxidized to \( \text{Fe}^{3+} \).
- The reduction of dichromate involves the transfer of electrons and the formation of water as a product.