Step 1: Understanding the Concept:
This question asks to compare the sum of three fractions to an integer. We can solve this either by finding the exact sum or by using estimation.
Step 2: Key Formula or Approach:
Method 1: Estimation
We can compare each fraction to 1.
\(\frac{13}{15}\) is less than 1 (since \(13 \textless 15\)). It is \(1 - \frac{2}{15}\).
\(\frac{7}{8}\) is less than 1 (since \(7 \textless 8\)). It is \(1 - \frac{1}{8}\).
\(\frac{3}{4}\) is less than 1 (since \(3 \textless 4\)). It is \(1 - \frac{1}{4}\).
The sum is the sum of three numbers, each of which is less than 1. Therefore, their sum must be less than \(1 + 1 + 1 = 3\).
This quick estimation shows that the quantity in Column A is less than the quantity in Column B.
Method 2: Exact Calculation
To find the exact sum, we need to find a common denominator for 15, 8, and 4.
The multiples of 15 are 15, 30, 45, 60, 75, 90, 105, 120, ...
The multiples of 8 are 8, 16, ..., 120, ...
The multiples of 4 are 4, 8, ..., 120, ...
The least common multiple (LCM) of 15, 8, and 4 is 120.
Now, convert each fraction to an equivalent fraction with a denominator of 120.
\[
\frac{13}{15} = \frac{13 \times 8}{15 \times 8} = \frac{104}{120}
\]
\[
\frac{7}{8} = \frac{7 \times 15}{8 \times 15} = \frac{105}{120}
\]
\[
\frac{3}{4} = \frac{3 \times 30}{4 \times 30} = \frac{90}{120}
\]
Now, add the fractions:
\[
\frac{104}{120} + \frac{105}{120} + \frac{90}{120} = \frac{104 + 105 + 90}{120} = \frac{299}{120}
\]
Step 3: Comparing the Quantities:
Column A: \(\frac{299}{120}\)
Column B: 3
To compare, we can write 3 as a fraction with a denominator of 120.
\[
3 = \frac{3 \times 120}{120} = \frac{360}{120}
\]
Comparing the numerators, we see that \(299 \textless 360\).
Therefore, \(\frac{299}{120} \textless 3\).
Step 4: Final Answer:
The quantity in Column A is less than the quantity in Column B. Both methods confirm this result.