Question

Cl--P--Cl bond angles in PCl\(_5\) molecule are

• A. \(120^\circ\) and \(90^\circ\)
• B. \(60^\circ\) and \(90^\circ\)
• C. \(60^\circ\) and \(120^\circ\)
• D. \(120^\circ\) and \(30^\circ\)

Hint:

Trigonal bipyramidal geometry has \(120^\circ\) between equatorial bonds and \(90^\circ\) between axial and equatorial bonds.

Answer 1

The Correct Option is A

Step 1: Identify the geometry of PCl\(_5\).
PCl\(_5\) has trigonal bipyramidal geometry.
Step 2: Axial and equatorial positions.
- 3 equatorial Cl atoms lie in one plane, separated by \(120^\circ\).
- 2 axial Cl atoms are perpendicular to the equatorial plane.
Step 3: Bond angles.
Equatorial--equatorial angle = \(120^\circ\).
Axial--equatorial angle = \(90^\circ\).
Step 4: Conclude.
Thus Cl--P--Cl angles are \(120^\circ\) and \(90^\circ\).
Final Answer:
\[ \boxed{120^\circ \text{ and } 90^\circ} \]