Question

CH\(_3\)CH\(_3\) + HNO\(_3\) \(\xrightarrow{675\,K}\)

• A. CH\(_3\)CH\(_2\)NO\(_2\)
• B. CH\(_3\)CH\(_2\)NO\(_2\) + CH\(_3\)NO\(_2\)
• C. 2CH\(_3\)NO\(_2\)
• D. CH\(_2\)=CH\(_2\)

Hint:

Alkanes react with HNO\(_3\) at high temperature to form nitroalkanes via free radical substitution.

Answer 1

The Correct Option is B

Step 1: Identify the reaction type.
Ethane reacts with nitric acid at high temperature (around 675 K) to give nitroalkanes via free radical substitution.
Step 2: Explain product formation.
In ethane, both carbon atoms are equivalent, but radical substitution can lead to formation of two nitro products due to different radical fragmentation pathways:
- Nitroethane: CH\(_3\)CH\(_2\)NO\(_2\)
- Nitromethane: CH\(_3\)NO\(_2\)
Step 3: Conclude the correct option.
Thus, the mixture of CH\(_3\)CH\(_2\)NO\(_2\) and CH\(_3\)NO\(_2\) is obtained.
Final Answer:
\[ \boxed{\text{(B) CH\(_3\)CH\(_2\)NO\(_2\) + CH\(_3\)NO\(_2\)}} \]