Calculate the steadystate current in the $2\,\Omega$ resistor shown in the circuit in the figure.
The internal resistance of the battery is negligible and the capacitance of the condenser $C$ is $0.2\, \mu F$.
Updated On: Jun 23, 2023
$0.6\,A$
$0.9\,A$
$1.2\,A$
$0.1\,A$
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The Correct Option isB
Solution and Explanation
At steady state, no current flows through the capacitor branch of the circuit.
$2\,\Omega$ and $3\,\Omega$ are in parallel. Let their combined resistance be $R$.
$\therefore R=\frac{2 \times 3}{2+3}=\frac{2\times3}{5}$$=1.2\,\Omega$
Net current supplied $=\frac{6}{1.2+2.8}$$I=1.5\,A$$I$ divides into $I_{1}$ and $I_{2}$$2I_{1}=3I_{2}\quad$ [Potential Difference is same]
or $I_2=2I_1/3$$I_{1}+I_{2}=1.5$ or $I_{1}+\frac{2I_{1}}{3}$$=1.5$
or $\frac{5I_{1}}{3}=1.5$ or $I_{1}=\frac{1.5 \times 3}{5}\,A$$=0.9\,A$
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
Alternating Current
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.
