Question

Calculate molar conductivity for 0.5 M BaCl\(_2\) if its conductivity at 298K is 0.01 \( \Omega^{-1} \text{cm}^{-1} \).

Hint:

For short-answer chemistry questions, ensure precise chemical formulas, unit derivations, and awareness of standard techniques or compounds used in specific contexts.

Answer 1

Molar conductivity \( \Lambda_m = \frac{\kappa \cdot 1000}{C} \), where \( \kappa = 0.01 \, \Omega^{-1} \text{cm}^{-1} \), \( C = 0.5 \, \text{mol dm}^{-3} = 0.5 \, \text{mol L}^{-1} = 500 \, \text{mol m}^{-3} \). Convert units: \[ \Lambda_m = \frac{0.01 \cdot 1000}{0.5} = \frac{10}{0.5} = 20 \, \Omega^{-1} \text{cm}^2 \text{mol}^{-1}. \]